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Solution :

Total number of ions in the rod <br> =number of ions per unit volume`xx` volume of rod <br> `=(2xx10^(25))xx3.14xx(0.005)^(2)xx(5xx10^(-2))` <br> `=7.85xx10^(19)` <br> The number of photons excited in one direction is equal to the total number of ions because all ions are excited Noe, excited energy <br> =number of excited photons`xx` energy of photon <br> `(7.85xx10^(19))xx(hc)/(lamda)` <br> `=(7.85xx10^(19))xx((6.6xx10^(-34))xx(3xx10^(8)))/(6.6xx10^(-7))` <br> `=23.55W`