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# Pure Hellspawn

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## About Pure Hellspawn

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1. ## Pure Hellspawn

Not sure where to put this, but I'm 100% stuck on two homework problems for chemistry and have spent at least 3 hours on it. The problems are as follows:

#1:

Consider the following reaction:
2 O3 ---> 3 O2
The rate law for this reaction is as follows:
Rate = k [O3]^2 / [O2]
Suppose that a 1.0 L reaction vessel initially contains 1.0 mol of O3 and 1.0 mol of O2.

What fraction of the O3 will have reacted when the rate falls to one-half of its initial value?

For this one I created an ICE chart, it looks like this:
O3 O2
I 1 1
C -2x +3x
E 1-2x 1+3x

I'm stuck after that. Oh boy.

#2:
The data below were collected for the following reaction at a certain temperature:

X2Y --> 2X + Y

Time Molarity
0.0 0.100
1.0 0.0856
2.0 0.0748
3.0 0.0664
4.0 0.0598
5.0 0.0543

I know this is a second order reaction but I need help finding the rate constant. I tried using the integrated rate law to no success.

Anyways, this is how the last three hours of my life have been going. Please help me. I need it badly.

1. Show previous comments  7 more
2. Pure Hellspawn said:

Not sure where to put this, but I'm 100% stuck on two homework problems for chemistry and have spent at least 3 hours on it. The problems are as follows:

#1:

Consider the following reaction:
2 O3 ---> 3 O2
The rate law for this reaction is as follows:
Rate = k [O3]^2 / [O2]
Suppose that a 1.0 L reaction vessel initially contains 1.0 mol of O3 and 1.0 mol of O2.

What fraction of the O3 will have reacted when the rate falls to one-half of its initial value?

Surely this is easy. They're initially in a 1:1 ratio, so the rate is k. You need to calculate the ratio when the rate is k/2, so

(O3)^2 = (O2)/2. [1]

The number of atoms never changes regardless of the reaction, so

O2 + O3 = 1 + 1
O2 = 2 - O3. [2]

Substitute [2] into [1]:

(O3)^2 = (2 - (O3)) / 2
(O3)^2 + (O3) / 2 - 1 = 0

Solve by the quadratic formula:

O3 = (-0.5 + sqrt(0.25 + 4)) / 2 = 0.78078

So you have 0.78078 mol of O3, 1.21922 mol of O2. This means that 0.21922 mol has been converted.

3. Csonicgo said:

if you remebmer the little formula for half life you should be able to figure the rest out.

Okay, let's see... scripted fights, linear levels, one-sided dialogue, more scripted fights... how does this help again?

4. fraggle said:

Genius

dude, I may need your help on some misc. aequilibria soon.

dammmn.

Creaphis said:

Okay, let's see... scripted fights, linear levels, one-sided dialogue, more scripted fights... how does this help again?

hahaha, I dunno man. I've been out of it the past few weeks, I've actually not been eating much(nothing but fruits and maybe a muffin) and in protest my body somehow gains weight. 185 to 215 eating fruit? Am I sleep eating?

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