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Not sure where to put this, but I'm 100% stuck on two homework problems for chemistry and have spent at least 3 hours on it. The problems are as follows:
#1:
Consider the following reaction:
2 O3 > 3 O2
The rate law for this reaction is as follows:
Rate = k [O3]^2 / [O2]
Suppose that a 1.0 L reaction vessel initially contains 1.0 mol of O3 and 1.0 mol of O2.
What fraction of the O3 will have reacted when the rate falls to onehalf of its initial value?
For this one I created an ICE chart, it looks like this:
O3 O2
I 1 1
C 2x +3x
E 12x 1+3x
I'm stuck after that. Oh boy.
#2:
The data below were collected for the following reaction at a certain temperature:
X2Y > 2X + Y
Time Molarity
0.0 0.100
1.0 0.0856
2.0 0.0748
3.0 0.0664
4.0 0.0598
5.0 0.0543
I know this is a second order reaction but I need help finding the rate constant. I tried using the integrated rate law to no success.
Anyways, this is how the last three hours of my life have been going. Please help me. I need it badly. Show previous comments 7 more

Pure Hellspawn said:
Not sure where to put this, but I'm 100% stuck on two homework problems for chemistry and have spent at least 3 hours on it. The problems are as follows:
#1:
Consider the following reaction:
2 O3 > 3 O2
The rate law for this reaction is as follows:
Rate = k [O3]^2 / [O2]
Suppose that a 1.0 L reaction vessel initially contains 1.0 mol of O3 and 1.0 mol of O2.
What fraction of the O3 will have reacted when the rate falls to onehalf of its initial value?
Surely this is easy. They're initially in a 1:1 ratio, so the rate is k. You need to calculate the ratio when the rate is k/2, so
(O3)^2 = (O2)/2. [1]
The number of atoms never changes regardless of the reaction, so
O2 + O3 = 1 + 1
O2 = 2  O3. [2]
Substitute [2] into [1]:
(O3)^2 = (2  (O3)) / 2
(O3)^2 + (O3) / 2  1 = 0
Solve by the quadratic formula:
O3 = (0.5 + sqrt(0.25 + 4)) / 2 = 0.78078
So you have 0.78078 mol of O3, 1.21922 mol of O2. This means that 0.21922 mol has been converted. 
fraggle said:
Genius
dude, I may need your help on some misc. aequilibria soon.
dammmn.
Creaphis said:Okay, let's see... scripted fights, linear levels, onesided dialogue, more scripted fights... how does this help again?
hahaha, I dunno man. I've been out of it the past few weeks, I've actually not been eating much(nothing but fruits and maybe a muffin) and in protest my body somehow gains weight. 185 to 215 eating fruit? Am I sleep eating?